A Comparison of Waves Forms For Prime Numbers 2 & 3 Against the Wave Form for All Integers.
A Comparison of the Waves Functions of Prime Numbers 2 & 3 Against the Wave Function of All Integers.

The Prime Equation

Primal Wave Interference

Equation Expressing All Prime Numbers as a Wave
Pa Represents a Wave that Passes through Every Prime Number & Their Multiples
Periodic Sine Wave Function Passing Through All Integers
Periodic Sine Wave Function Passing Through a Prime & Every Multiple of the Prime

Solve for 0:

Periodic Wave Function Passing Through All Integers
Periodic Wave Function Passing Through The Prime Number 2 & Every Multiple of Prime Number 2
wave functions for all integers and prime of 2
wave functions solved for 0 with interference pattern
wave functions solved for 0 without interference pattern

Solving for p₂:

A Comparison of Waves Forms For Prime Numbers 2 & 3 Against the Wave Form for All Integers.

Solving for p₃:

Solving for p₄:

Conclusion:

Bonus 1:

Build Your Own Equation Expressed as a Dynamic Prime Wave:

Bonus 2:

# <<< imported python libraries/commands >>>
import math
# <<< program functions >>># <<< variables >>>
pi =round(2*(math.acos(0.0)), 10)

# <<< Comparing wave expression for all integers against wave expression for prime numbers >>>
def p1():
x=1
while x >= 1:
x += 1
f0 = round(math.sin(pi*x))
f1 = round(math.sin((pi*x)/2))

if f0 == (f1):
return(round(x))
def p2():
x=1
while x >= 1:
x += 1
f0 = round(math.sin(pi*x))
f1 = round(math.sin((pi*x)/p1()))

if f0 != (f1):
return(round(x))
def p3():
x=1
while x >= 1:
x += 1

f0 = round(math.sin(pi*x))
f1 = round(math.sin((pi*x)/p1()))
f2 = round(math.sin((pi*x)/p2()))

if f0 != (f1 * f2):
return(round(x))
def p4():
x=1
while x >= 1:
x += 1

f0 = round(math.sin(pi*x))
f1 = round(math.sin((pi*x)/p1()))
f2 = round(math.sin((pi*x)/p2()))
f3 = round(math.sin((pi*x)/p3()))

if f0 != (f1 * f2 * f3):
return(round(x))
def p5():
x=1
while x >= 1:
x += 1

f0 = round(math.sin(pi*x))
f1 = round(math.sin((pi*x)/p1()))
f2 = round(math.sin((pi*x)/p2()))
f3 = round(math.sin((pi*x)/p3()))
f4 = round(math.sin((pi*x)/p4()))

if f0 != (f1 * f2 * f3 * f4):
return(round(x))

Human Being, b. circa 1990 ~ planet Terra, Via Lactea Galaxia